X, Y and Z are three contestants in a race of 1000 m. Assume that all run with different uniform speeds. X gives Y a start of 40 m and X gives Z a start of 64 m. If Y and Z were to compete in a race of 1000 m, how many metres start will Y give to Z?
20
25
30
35
Answer is (b). In the 1000 m race, X gives Y 40 m start. That means Y starts race 40 m ahead of X. In the 1000 m race, X gives Z 64 m start. That means Z starts race 64 m ahead of X So, this means Y gives a lead of 24 m in a 1000 – 40 = 960 m race. So, by unitary method, lead given by Y in 1000 m = 24/960×1000 = 25 m.
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