There are three points P, Q and R on a straight line such that PQ:QR = 3:5. If n is the number of possible values of PQ:PR, then what is n equal to ?
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We have to arrange three points P, Q, and R on a straight line, such that PQ : QR = 3 : 5 Three points can be arranged in 3!, i.e. 6 ways. However, the number of possible values of PQ : PR will be only 2, i.e. n = 2. They have been represented below.
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