How many 3-digit natural numbers (without repetition of digits) are there such that each digit is odd and the number is divisible by 5?
8
12
16
24
We need to find three-digit numbers in which: All digits are odd. So, the three digits must be from amongst 1, 3, 5, 7, and 9. The number is divisible by 5, i.e. the units digit is 5. The number of ways we can fill the first two digits from amongst 4 distinct digits = 4 × 3 = 12.
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