A three-digit number is such that is ten’s digit is 1 and the unit’s digit exceeds the hundred’s digit by 3. The number, when reversed and added to the original number, gives the sum as 727. What is the reversed number?
512
114
316
714
Let the original number be 100x + Y + z; such that y = 1 and z = x+3.
Hence, the original number is 100x + 10 + z and the reversed number is 100z + 10 + x.
Their sum is 727.
100x + 10 + z + 100z + 10 + x = 727
101X + 101Z+20=727
101 (x + z) = 707
(x + z ) = 7
(x + x + 3) = 7
2x = 4 i.e. x = 2
Hence, the original number is 215 and the reversed number is 512.
Hence option-A is the answer.
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